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Python Set

A Python set is the collection of the unordered items. Each element in the set must be unique, immutable, and the sets remove the duplicate elements. Sets are mutable which means we can modify it after its creation.

Unlike other collections in Python, there is no index attached to the elements of the set, i.e., we cannot directly access any element of the set by the index. However, we can print them all together, or we can get the list of elements by looping through the set.

Creating a set

The set can be created by enclosing the comma-separated immutable items with the curly braces {}. Python also provides the set() method, which can be used to create the set by the passed sequence.

Example 1: Using curly braces

     Days = {"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"}  
print(Days)  
print(type(Days))  
print("looping through the set elements ... ")  
for i in Days:  
    print(i)  

    

Output:

{'Friday', 'Tuesday', 'Monday', 'Saturday', 'Thursday', 'Sunday', 'Wednesday'}

looping through the set elements ... 
Friday
Tuesday
Monday
Saturday
Thursday
Sunday
Wednesday

Example 2: Using set() method

     Days = set(["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"])  
print(Days)  
print(type(Days))  
print("looping through the set elements ... ")  
for i in Days:  
    print(i)  

    

Output:

{'Friday', 'Wednesday', 'Thursday', 'Saturday', 'Monday', 'Tuesday', 'Sunday'}

looping through the set elements ... 
Friday
Wednesday
Thursday
Saturday
Monday
Tuesday
Sunday

It can contain any type of element such as integer, float, tuple etc. But mutable elements (list, dictionary, set) can't be a member of set. Consider the following example.

     # Creating a set which have immutable elements
set1 = {1,2,3, "JavaTpoint", 20.5, 14}
print(type(set1))
#Creating a set which have mutable element
set2 = {1,2,3,["Javatpoint",4]}
print(type(set2))

    

Output:



Traceback (most recent call last)
 in 
      4 
      5 #Creating a set which holds mutable elements
----> 6 set2 = {1,2,3,["Javatpoint",4]}
      7 print(type(set2))

TypeError: unhashable type: 'list'

In the above code, we have created two sets, the set set1 have immutable elements and set2 have one mutable element as a list. While checking the type of set2, it raised an error, which means set can contain only immutable elements.

Creating an empty set is a bit different because empty curly {} braces are also used to create a dictionary as well. So Python provides the set() method used without an argument to create an empty set.

     # Empty curly braces will create dictionary
set3 = {}
print(type(set3))

# Empty set using set() function
set4 = set()
print(type(set4))

    

Output:

Let's see what happened if we provide the duplicate element to the set.

     set5 = {1,2,4,4,5,8,9,9,10}
print("Return set with unique elements:",set5)

Output:

Return set with unique elements: {1, 2, 4, 5, 8, 9, 10}

In the above code, we can see that set5 consisted of multiple duplicate elements when we printed it remove the duplicity from the set.

Adding items to the set

Python provides the add() method and update() method which can be used to add some particular item to the set. The add() method is used to add a single element whereas the update() method is used to add multiple elements to the set. Consider the following example.

Example: 1 - Using add() method

     Months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(months)  
print("\nAdding other months to the set...");  
Months.add("July");  
Months.add ("August");  
print("\nPrinting the modified set...");  
print(Months)  
print("\nlooping through the set elements ... ")  
for i in Months:  
    print(i)  

    

Output:

printing the original set ... 
{'February', 'May', 'April', 'March', 'June', 'January'}

Adding other months to the set...

Printing the modified set...
{'February', 'July', 'May', 'April', 'March', 'August', 'June', 'January'}

looping through the set elements ... 
February
July
May
April
March
August
June
January

To add more than one item in the set, Python provides the update() method. It accepts iterable as an argument.

Consider the following example.

Example - 2 Using update() function

     Months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(Months)  
print("\nupdating the original set ... ")  
Months.update(["July","August","September","October"]);  
print("\nprinting the modified set ... ")   
print(Months);

    

Output:

printing the original set ... 
{'January', 'February', 'April', 'May', 'June', 'March'}

updating the original set ... 
printing the modified set ... 
{'January', 'February', 'April', 'August', 'October', 'May', 'June', 'July', 'September', 'March'}

Removing items from the set

Python provides the discard() method and remove() method which can be used to remove the items from the set. The difference between these function, using discard() function if the item does not exist in the set then the set remain unchanged whereas remove() method will through an error.

Consider the following example.

Example-1 Using discard() method

     months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(months)  
print("\nRemoving some months from the set...");  
months.discard("January");  
months.discard("May");  
print("\nPrinting the modified set...");  
print(months)  
print("\nlooping through the set elements ... ")  
for i in months:  
    print(i)  

    

Output:

printing the original set ... 
{'February', 'January', 'March', 'April', 'June', 'May'}

Removing some months from the set...

Printing the modified set...
{'February', 'March', 'April', 'June'}

looping through the set elements ... 
February
March
April
June

Python provides also the remove() method to remove the item from the set. Consider the following example to remove the items using remove() method.

Example-2 Using remove() function

     months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(months)  
print("\nRemoving some months from the set...");  
months.remove("January");  
months.remove("May");  
print("\nPrinting the modified set...");  
print(months)  

    

Output:

printing the original set ... 
{'February', 'June', 'April', 'May', 'January', 'March'}

Removing some months from the set...

Printing the modified set...
{'February', 'June', 'April', 'March'}

We can also use the pop() method to remove the item. Generally, the pop() method will always remove the last item but the set is unordered, we can't determine which element will be popped from set.

Consider the following example to remove the item from the set using pop() method.

     Months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(Months)  
print("\nRemoving some months from the set...");  
Months.pop();  
Months.pop();  
print("\nPrinting the modified set...");  
print(Months)  

    

Output:

printing the original set ... 
{'June', 'January', 'May', 'April', 'February', 'March'}

Removing some months from the set...

Printing the modified set...
{'May', 'April', 'February', 'March'}

In the above code, the last element of the Month set is March but the pop() method removed the June and January because the set is unordered and the pop() method could not determine the last element of the set.

Python provides the clear() method to remove all the items from the set.

Consider the following example.

     Months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(Months)  
print("\nRemoving all the items from the set...");  
Months.clear()  
print("\nPrinting the modified set...")  
print(Months)  

    

Output:

printing the original set ... 
{'January', 'May', 'June', 'April', 'March', 'February'}

Removing all the items from the set...

Printing the modified set...
set()

Difference between discard() and remove()

Despite the fact that discard() and remove() method both perform the same task, There is one main difference between discard() and remove().

If the key to be deleted from the set using discard() doesn't exist in the set, the Python will not give the error. The program maintains its control flow.

On the other hand, if the item to be deleted from the set using remove() doesn't exist in the set, the Python will raise an error.

Consider the following example.

Example-

     Months = set(["January","February", "March", "April", "May", "June"])  
print("\nprinting the original set ... ")  
print(Months)  
print("\nRemoving items through discard() method...");  
Months.discard("Feb"); #will not give an error although the key feb is not available in the set  
print("\nprinting the modified set...")  
print(Months)  
print("\nRemoving items through remove() method...");  
Months.remove("Jan") #will give an error as the key jan is not available in the set.   
print("\nPrinting the modified set...")  
print(Months)  

    

Output:

printing the original set ... 
{'March', 'January', 'April', 'June', 'February', 'May'}

Removing items through discard() method...

printing the modified set...
{'March', 'January', 'April', 'June', 'February', 'May'}

Removing items through remove() method...
Traceback (most recent call last):
  File "set.py", line 9, in 
    Months.remove("Jan")
KeyError: 'Jan'

Python Set Operations

Set can be performed mathematical operation such as union, intersection, difference, and symmetric difference. Python provides the facility to carry out these operations with operators or methods. We describe these operations as follows.

Union of two Sets

The union of two sets is calculated by using the pipe (|) operator. The union of the two sets contains all the items that are present in both the sets.

Consider the following example to calculate the union of two sets.

Example 1: using union | operator

     Days1 = {"Monday","Tuesday","Wednesday","Thursday", "Sunday"}  
Days2 = {"Friday","Saturday","Sunday"}  
print(Days1|Days2) #printing the union of the sets   

    

Output:

{'Friday', 'Sunday', 'Saturday', 'Tuesday', 'Wednesday', 'Monday', 'Thursday'}

Python also provides the union() method which can also be used to calculate the union of two sets. Consider the following example.

Example 2: using union() method

     Days1 = {"Monday","Tuesday","Wednesday","Thursday"}  
Days2 = {"Friday","Saturday","Sunday"}  
print(Days1.union(Days2)) #printing the union of the sets   

    

Output:

{'Friday', 'Monday', 'Tuesday', 'Thursday', 'Wednesday', 'Sunday', 'Saturday'}

Intersection of two sets

The intersection of two sets can be performed by the and & operator or the intersection() function. The intersection of the two sets is given as the set of the elements that common in both sets.

Consider the following example.

Example 1: Using & operator

     Days1 = {"Monday","Tuesday", "Wednesday", "Thursday"}  
Days2 = {"Monday","Tuesday","Sunday", "Friday"}  
print(Days1&Days2) #prints the intersection of the two sets  

    

Output:

{'Monday', 'Tuesday'}

Example 2: Using intersection() method

     set1 = {"Devansh","John", "David", "Martin"}  
set2 = {"Steve", "Milan", "David", "Martin"}  
print(set1.intersection(set2)) #prints the intersection of the two sets  

    

Output:

{'Martin', 'David'}

Example 3:

     set1 = {1,2,3,4,5,6,7}
set2 = {1,2,20,32,5,9}
set3 = set1.intersection(set2)
print(set3)

    

Output:

{1,2,5}

The intersection_update() method

The intersection_update() method removes the items from the original set that are not present in both the sets (all the sets if more than one are specified).

The intersection_update() method is different from the intersection() method since it modifies the original set by removing the unwanted items, on the other hand, the intersection() method returns a new set.

Consider the following example.

     a = {"Devansh", "bob", "castle"}  
b = {"castle", "dude", "emyway"}  
c = {"fuson", "gaurav", "castle"}  
  
a.intersection_update(b, c)  
  
print(a)

Output:

{'castle'}

Difference between the two sets

The difference of two sets can be calculated by using the subtraction (-) operator or intersection() method. Suppose there are two sets A and B, and the difference is A-B that denotes the resulting set will be obtained that element of A, which is not present in the set B.

Consider the following example.

Example 1 : Using subtraction ( - ) operator

     Days1 = {"Monday",  "Tuesday", "Wednesday", "Thursday"}  
Days2 = {"Monday", "Tuesday", "Sunday"}  
print(Days1-Days2) #{"Wednesday", "Thursday" will be printed}  

    

Output:

{'Thursday', 'Wednesday'}

Example 2 : Using difference() method

     Days1 = {"Monday",  "Tuesday", "Wednesday", "Thursday"}  
Days2 = {"Monday", "Tuesday", "Sunday"}  
print(Days1.difference(Days2)) # prints the difference of the two sets Days1 and Days2  

    

Output:

{'Thursday', 'Wednesday'}

Symmetric Difference of two sets

The symmetric difference of two sets is calculated by ^ operator or symmetric_difference() method. Symmetric difference of sets, it removes that element which is present in both sets. Consider the following example:

Example - 1: Using ^ operator

     a = {1,2,3,4,5,6}
b = {1,2,9,8,10}
c = a^b
print(c)

    

Output:

{3, 4, 5, 6, 8, 9, 10}

Example - 2: Using symmetric_difference() method

     a = {1,2,3,4,5,6}
b = {1,2,9,8,10}
c = a.symmetric_difference(b)
print(c)

    

Output:

{3, 4, 5, 6, 8, 9, 10}

Set comparisons

Python allows us to use the comparison operators i.e., <, >, <=, >= , == with the sets by using which we can check whether a set is a subset, superset, or equivalent to other set. The boolean true or false is returned depending upon the items present inside the sets.

Consider the following example.

     Days1 = {"Monday",  "Tuesday", "Wednesday", "Thursday"}  
Days2 = {"Monday", "Tuesday"}  
Days3 = {"Monday", "Tuesday", "Friday"}  
  
#Days1 is the superset of Days2 hence it will print true.   
print (Days1>Days2)   
  
#prints false since Days1 is not the subset of Days2   
print (Days1<Days2)  
  
#prints false since Days2 and Days3 are not equivalent   
print (Days2 == Days3)  

    

Output:

True
False
False

FrozenSets

The frozen sets are the immutable form of the normal sets, i.e., the items of the frozen set cannot be changed and therefore it can be used as a key in the dictionary.

The elements of the frozen set cannot be changed after the creation. We cannot change or append the content of the frozen sets by using the methods like add() or remove().

The frozenset() method is used to create the frozenset object. The iterable sequence is passed into this method which is converted into the frozen set as a return type of the method.

Consider the following example to create the frozen set.

     Frozenset = frozenset([1,2,3,4,5])   
print(type(Frozenset))  
print("\nprinting the content of frozen set...")  
for i in Frozenset:  
    print(i);  
Frozenset.add(6) #gives an error since we cannot change the content of Frozenset after creation   

    

Output:



printing the content of frozen set...
1
2
3
4
5
Traceback (most recent call last):
  File "set.py", line 6, in 
    Frozenset.add(6) #gives an error since we can change the content of Frozenset after creation 
AttributeError: 'frozenset' object has no attribute 'add'

Frozenset for the dictionary

If we pass the dictionary as the sequence inside the frozenset() method, it will take only the keys from the dictionary and returns a frozenset that contains the key of the dictionary as its elements.

Consider the following example.

     Dictionary = {"Name":"John", "Country":"USA", "ID":101}   
print(type(Dictionary))  
Frozenset = frozenset(Dictionary); #Frozenset will contain the keys of the dictionary  
print(type(Frozenset))  
for i in Frozenset:   
    print(i)  

    

Output:



Name
Country
ID

Set Programming Example

Example - 1: Write a program to remove the given number from the set.

     my_set = {1,2,3,4,5,6,12,24}
n = int(input("Enter the number you want to remove"))
my_set.discard(n)
print("After Removing:",my_set)

    

Output:

Enter the number you want to remove:12
After Removing: {1, 2, 3, 4, 5, 6, 24}

Example - 2: Write a program to add multiple elements to the set.

     set1 = set([1,2,4,"John","CS"])
set1.update(["Apple","Mango","Grapes"])
print(set1)

    

Output:

{1, 2, 4, 'Apple', 'John', 'CS', 'Mango', 'Grapes'}

Example - 3: Write a program to find the union between two set.

     set1 = set(["Peter","Joseph", 65,59,96])
set2  = set(["Peter",1,2,"Joseph"])
set3 = set1.union(set2)
print(set3)

    

Output:

{96, 65, 2, 'Joseph', 1, 'Peter', 59}

Example- 4: Write a program to find the intersection between two sets.

     set1 = {23,44,56,67,90,45,"Javatpoint"}
set2 = {13,23,56,76,"Sachin"}
set3 = set1.intersection(set2)
print(set3)

    

Output:

{56, 23}

Example - 5: Write the program to add element to the frozenset.

     set1 = {23,44,56,67,90,45,"Javatpoint"}
set2 = {13,23,56,76,"Sachin"}
set3 = set1.intersection(set2)
print(set3)

    

Output:

TypeError: 'frozenset' object does not support item assignment

Above code raised an error because frozensets are immutable and can't be changed after creation.

Example - 6: Write the program to find the issuperset, issubset and superset.

     set1 = set(["Peter","James","Camroon","Ricky","Donald"])
set2 = set(["Camroon","Washington","Peter"])
set3 = set(["Peter"])

issubset = set1 >= set2
print(issubset)
issuperset = set1 <= set2
print(issuperset)
issubset = set3 <= set2
print(issubset)
issuperset = set2 >= set3
print(issuperset)

    

Output:

False
False
True
True

Python Built-in set methods

Python contains the following methods to be used with the sets.

SN	Method	Description
1	add(item)	It adds an item to the set. It has no effect if the item is already present in the set.
2	clear()	It deletes all the items from the set.
3	copy()	It returns a shallow copy of the set.
4	difference_update(....)	It modifies this set by removing all the items that are also present in the specified sets.
5	discard(item)	It removes the specified item from the set.
6	intersection()	It returns a new set that contains only the common elements of both the sets. (all the sets if more than two are specified).
7	intersection_update(....)	It removes the items from the original set that are not present in both the sets (all the sets if more than one are specified).
8	Isdisjoint(....)	Return True if two sets have a null intersection.
9	Issubset(....)	Report whether another set contains this set.
10	Issuperset(....)	Report whether this set contains another set.
11	pop()	Remove and return an arbitrary set element that is the last element of the set. Raises KeyError if the set is empty.
12	remove(item)	Remove an element from a set; it must be a member. If the element is not a member, raise a KeyError.
13	symmetric_difference(....)	Remove an element from a set; it must be a member. If the element is not a member, raise a KeyError.
14	symmetric_difference_update(....)	Update a set with the symmetric difference of itself and another.
15	union(....)	Return the union of sets as a new set. (i.e. all elements that are in either set.)
16	update()	Update a set with the union of itself and others.